Ivan Shishkin, Birch Grove

Contravariant hom functor

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Revision 591

7/25/2026, 10:09:29 AM · Ancient Tree

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1Let $\mathcal{C}$ be a [[Locally small category|locally small category]]. For each object $B$ in $\mathcal{C}$, there is a [[Functor|functor]]
2$$\operatorname{Hom}_{\mathcal{C}}(-,B):\mathcal{C}^{\operatorname{op}}\rightarrow \mathbf{Set}$$
3defined by:
4- On objects: each object $X$ is sent to the set $\operatorname{Hom}_{\mathcal{C}}(X,B)$.
5- On morphisms: a morphism $f:X\rightarrow Y$ is sent to the function
6$$f^*=\operatorname{Hom}_{\mathcal{C}}(f, B): \operatorname{Hom}_{\mathcal{C}}(Y, B) \rightarrow \operatorname{Hom}_{\mathcal{C}}(X, B)$$
7given by pre-composition: $g\mapsto g\circ f$.
7given by [[Pre-composition|pre-composition]]: $g\mapsto g\circ f$.

Revision 589

7/25/2026, 10:08:10 AM · Ancient Tree

Concept created

Let $\mathcal{C}$ be a [[Locally small category|locally small category]]. For each object $B$ in $\mathcal{C}$, there is a [[Functor|functor]]
$$\operatorname{Hom}_{\mathcal{C}}(-,B):\mathcal{C}^{\operatorname{op}}\rightarrow \mathbf{Set}$$
defined by:
- On objects: each object $X$ is sent to the set $\operatorname{Hom}_{\mathcal{C}}(X,B)$.
- On morphisms: a morphism $f:X\rightarrow Y$ is sent to the function
$$f^*=\operatorname{Hom}_{\mathcal{C}}(f, B): \operatorname{Hom}_{\mathcal{C}}(Y, B) \rightarrow \operatorname{Hom}_{\mathcal{C}}(X, B)$$
given by pre-composition: $g\mapsto g\circ f$.