Increasing function
Concept history
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Revision 821
8/1/2026, 7:10:50 PM · Sequoia
Concept edited
Recorded titleIncreasing function
Recorded typeDefinition
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A [[Function|function]] $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x\leqslant y$, then $f(x)\leq f(y)$.1
A [[Function|function]] $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x\leqslant y$, then $f(x)\leqslant f(y)$.Revision 820
8/1/2026, 7:10:38 PM · Sequoia
Concept edited
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1
A [[Function|function]] $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x<y$, then $f(x)\leq f(y)$.1
A [[Function|function]] $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x\leqslant y$, then $f(x)\leq f(y)$.Revision 668
7/27/2026, 1:01:51 PM · Ancient Tree
Concept edited
Compare with revision 6672 changed lines
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A function $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x<y$, then $f(x)\leq f(y)$.1
A [[Function|function]] $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x<y$, then $f(x)\leq f(y)$.Revision 667
7/27/2026, 1:01:42 PM · Ancient Tree
Concept created
A function $f:A \rightarrow \R$ defined on a subset $A\subseteq \R$ is increasing if, for every $x,y\in A$, whenever $x<y$, then $f(x)\leq f(y)$.