
Monoid
Concept history
A revision trail for this concept page.
Revision 812
8/1/2026, 5:42:03 PM · Sequoia
Concept edited
Recorded titleMonoid
Recorded typeDefinition
Compare with revision 8082 changed lines
1
A monoid $(M,*)$ is a [[unital|unital magma]] such that the law $*$ is associative, which means that for all $x,y,z\in M$, one has the equality:1
A monoid $(M,*)$ is a [[unital|unital magma]] such that the [[Operation|binary operation]] $*$ is associative, which means that for all $x,y,z\in M$, one has the equality:2
$$3
(x*y)*z=x*(y*z)4
$$5
**Examples:**6
7
$\bullet$ The magma $(\Z,-)$ is not a monoid since $(1-2)-3=-4\neq 2=1-(2-3)$.8
9
$\bullet$ The magma $(\Z,+)$ is a monoid since $(a+b)+c=a+(b+c)$ for all $a,b,c\in\Z$ and $0$ is an identity element.Revision 808
8/1/2026, 5:33:01 PM · Sequoia
Concept edited
Compare with revision 7868 changed lines
1
A monoid $(M,*)$ is a magma such that the law $*$ is associative, which means that for all $x,y,z\in M$, one has the equality:1
A monoid $(M,*)$ is a [[unital|unital magma]] such that the law $*$ is associative, which means that for all $x,y,z\in M$, one has the equality:2
$$3
(x*y)*z=x*(y*z)4
$$5
Examples:5
**Examples:**6
6
$\bullet$ The magma $(\Z,-)$ is not a monoid since $(1-2)-3=-4\neq 2=1-(2-3)$.7
$\bullet$ The magma $(\Z,+)$ is a monoid since $(a+b)+c=a+(b+c)$ for all $a,b,c\in\Z$.8
9
$\bullet$ The magma $(\Z,+)$ is a monoid since $(a+b)+c=a+(b+c)$ for all $a,b,c\in\Z$ and $0$ is an identity element.Revision 786
8/1/2026, 9:40:00 AM · Sequoia
Concept edited
This older revision predates detailed metadata tracking.
Revision 785
8/1/2026, 9:39:50 AM · Sequoia
Concept edited
This older revision predates detailed metadata tracking.
Revision 750
7/31/2026, 10:05:18 AM · Sequoia
Concept created
A monoid $(M,*)$ is a magma such that the law $*$ is associative, which means that for all $x,y,z\in M$, one has the equality: $$ (x*y)*z=x*(y*z) $$ Examples: $\bullet$ The magma $(\Z,-)$ is not a monoid since $(1-2)-3=-4\neq 2=1-(2-3)$. $\bullet$ The magma $(\Z,+)$ is a monoid since $(a+b)+c=a+(b+c)$ for all $a,b,c\in\Z$.