
-subgroup
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Revision 1008
8/6/2026, 9:36:55 PM · Sequoia
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A $p$-subgroup of a [[Finite group|finite group]] $G$ is a [[Subgroup|subgroup]] $H$ of $G$ which is a $p$[[$p$-group|-group]], that is, whose [[Order of a finite group|order]] is a power of $p$:1
Let $p$ be a [[Prime number|prime number]]. A $p$-subgroup of a [[Finite group|finite group]] $G$ is a [[Subgroup|subgroup]] $H$ of $G$ which is a $p$[[$p$-group|-group]], that is, whose [[Order of a finite group|order]] is a power of $p$:2
$$|H|=p^{k}$$3
for some $k\geq 0$Revision 1006
8/6/2026, 9:34:31 PM · Sequoia
Concept marked usable
statusStubUsable
Revision 963
8/6/2026, 12:52:10 PM · Ancient Tree
Updated text
Compare with revision 9612 changed lines
1
A $p$-subgroup of a [[Finite group|finite group]] $G$ is a [[Subgroup|subgroup]] $H$ of $G$ which is a $p$-group, that is, whose [[Order of a finite group|order]] is a power of $p$:1
A $p$-subgroup of a [[Finite group|finite group]] $G$ is a [[Subgroup|subgroup]] $H$ of $G$ which is a $p$[[$p$-group|-group]], that is, whose [[Order of a finite group|order]] is a power of $p$:2
$$|H|=p^{k}$$3
for some $k\geq 0$Revision 961
8/6/2026, 12:49:22 PM · Ancient Tree
Concept created
A $p$-subgroup of a [[Finite group|finite group]] $G$ is a [[Subgroup|subgroup]] $H$ of $G$ which is a $p$-group, that is, whose [[Order of a finite group|order]] is a power of $p$:
$$|H|=p^{k}$$
for some $k\geq 0$