Ivan Shishkin, Birch Grove

Kernel of an action; faithful, free, transitive, simply transitive actions

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Intuitive definition

The kernel measures what the action "does not see" of GG; the action is faithful when it sees everything. It is transitive when XX is in one piece (a single orbit), free when no non-trivial element fixes any point, simply transitive when every point can be sent to every other in exactly one way.

Formal definition

Let GG act on XX and let τ:G→S(X)\tau : G \to \mathfrak{S}(X) be the associated homomorphism.

  • The kernel of the action is
    ker⁡τ={g∈G∣∀x∈X, g⋅x=x}=⋂x∈XGx.\ker \tau = \{ g \in G \mid \forall x \in X,\ g \cdot x = x \} = \bigcap_{x \in X} G_x .It is a normal subgroup of GG.
  • The action is faithful if ker⁡τ={e}\ker \tau = \{e\}: then GG identifies with a subgroup of S(X)\mathfrak{S}(X).
  • The action is free if all stabilizers are trivial: g⋅x=x⇒g=eg \cdot x = x \Rightarrow g = e.
  • The action is transitive if there is only one orbit: for all x,y∈Xx, y \in X there exists g∈Gg \in G with y=g⋅xy = g \cdot x. One says XX is a homogeneous space under GG.
  • The action is simply transitive if it is free and transitive: for all x,yx, y there is a unique gg with y=g⋅xy = g \cdot x. One says XX is a GG-torsor (principal homogeneous space).
  • The action is kk-transitive if it is transitive on kk-tuples of pairwise distinct elements.

Properties

  • Free implies faithful; the converse fails (see example 4).
  • Any action induces a faithful action of the quotient G/ker⁡τG/\ker \tau on XX.
  • If the action is transitive, XX is in bijection with G/GxG/G_x for any xx (orbit-stabilizer theorem); if it is simply transitive, XX is in bijection with GG, but the bijection depends on the choice of a base point.

Examples

  1. Free, not transitive. Z\mathbb{Z} on R\mathbb{R} by translation n⋅x=x+nn \cdot x = x + n.
  2. Transitive, faithful, not free. Sn\mathfrak{S}_n on {1,…,n}\{1, \ldots, n\} for n≥3n \geq 3: it is even nn-transitive, and An\mathfrak{A}_n is (n−2)(n-2)-transitive.
  3. Simply transitive. GG on itself by left translation; GLn(K)\mathrm{GL}_n(K) on the bases of KnK^n; On(R)\mathrm{O}_n(\mathbb{R}) on the orthonormal bases of Rn\mathbb{R}^n; the additive group (E,+)(E, +) of a vector space on an affine space with direction EE (this is the very definition of an affine space).
  4. Faithful, not free. S3\mathfrak{S}_3 on the 22-element subsets of {1,2,3}\{1, 2, 3\}: a permutation fixing every pair fixes their intersections, hence every point, so the action is faithful; but Stab⁡({1,2})={id,(1 2)}\operatorname{Stab}(\{1, 2\}) = \{ \mathrm{id}, (1\ 2) \}.
  5. Not faithful. GG on itself by conjugation: the kernel is the center Z(G)Z(G). GLn(K)\mathrm{GL}_n(K) on the lines of KnK^n: the kernel is the group of homotheties K∗InK^\ast I_n, whence the faithful action of PGLn(K)\mathrm{PGL}_n(K) on projective space.
  6. GG on G/HG/H by translation: transitive, with kernel ⋂g∈GgHg−1\bigcap_{g \in G} g H g^{-1}, the largest normal subgroup of GG contained in HH (extended Cayley theorem).

Remarks

  • Classical pitfall. Do not confuse free and faithful: free means every stabilizer is trivial, faithful means the intersection of the stabilizers is trivial.
  • To prove transitivity: either exhibit explicitly gg sending xx to yy, or count and show ∣G⋅x∣=∣X∣|G \cdot x| = |X|.
  • To prove faithfulness: show that every g≠eg \neq e moves at least one point.
  • Pour prouver la fidélité : montrer que tout g≠eg \neq e déplace au moins un point.
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References

  1. Perrin, Daniel — Cours d’algèbre (Ellipses)
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