Ivan Shishkin, Rye (1878)

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Equations of an ellipse ?

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Solution

Solution by Ancient Tree · EN

  1. This equation does not admit any solution, because x2+2y2x^{2}+2y^{2} is always non-negative. So it’s not an ellipse.

  2. This is the equation of a circle of radius 2\sqrt{2}, which is a particular case of an ellipse (cf below).

  3. This is the equation of an ellipse of center (0,0)(0,0) with a=3a=3 and b=2b=2.

  4. This equation implies x=0x=0 and y=0y=0 because squares are always non-negative. So the set it defines is just a point. By convention, this is usually not considered an ellipse.

  5. This is the equation of an hyperbola, which is not an ellipse (because it is not bounded).

  6. Using x2+2x=(x+1)21x^2+2x=(x+1)^2-1, one gets (x+1)2+2y2=2(x+1)^2+2y^2=2 or also (x(1)2)2+(y01)2=1\left(\frac{x-(-1)}{\sqrt{2}}\right)^2+\left(\frac{y-0}{1}\right)^2=1 which is an ellipse.

  7. The equation of a circle is (xx0)2+(yy0)2=R2(x-x_0)^2+(y-y_0)^2=R^2 then, dividing by R2R^2, one gets the cartesian equation of an ellipse with a=ba=b.

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