Ivan Shishkin, Rye (1878)

Problems/FieldExerciseReviewed

Field extensions of C\mathbb{C} of degree 2

by Ancient Tree·
41
Difficulty scaleÉchelle de difficulté

This score reflects both the level of the required concepts and the difficulty of the solution.Ce score tient compte à la fois du niveau des notions nécessaires et de la difficulté de la résolution.

  1. 110First steps / middle schoolPremiers pas / collège
  2. 1125Beginner / high schoolDébutant / lycée
  3. 2650Intermediate / undergraduateIntermédiaire / licence
  4. 5170Advanced / graduateAvancé / master
  5. 7190Expert / specializedExpert / spécialisé
  6. 91100Research levelNiveau recherche
These levels are approximate guides.Ces niveaux sont des repères approximatifs.
·
English

Show that C\mathbb{C} does not have a field extension of degree 2.

I solved itMark it doneAdd to my listKeep it in your list

Solutions

1
Reveal solutionsAre you sure? Give it a try first.

Solution by Ancient Tree

Discussions1 useful vote

Suppose that EE is a field extension of degree 22 of C\mathbb{C}, and let xx be an element of E\CE\backslash\mathbb{C}. By definition of degree, we have that the family (1,x)(1,x) forms a basis of EE (viewed as a vector space over C\mathbb{C}). In particular, this means that x2x^{2} can be written as a linear combination:
x2=ax+bx^{2}=ax+bwhere aa and bb are complex numbers. But any root of a complex polynomial, here X2aXbX^2-aX-b is in C\mathbb{C}. This means that xx is still in C\mathbb{C}, which is absurd.

Report

For an unclear, ambiguous, or possibly incorrect statement, please use the Discussion tab on the right. Report content that needs moderator intervention, such as dangerous, clearly non-mathematical, or plagiarized content.