Ivan Shishkin, Rye (1878)

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Field homomorphisms from C\mathbb{C} to R\R

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Solution

Solution by Ancient Tree · EN

Assume that such a φ:C→R\varphi:\mathbb{C}\rightarrow \R exists. Then, by definition of a field homomorphism,
φ(−1)=φ(i2)=φ(i)2\varphi(-1)=\varphi(i^{2})=\varphi(i)^{2}but φ(−1)=−φ(1)=−1\varphi(-1)=-\varphi(1)=-1. We therefore obtained that the real number φ(i)\varphi(i) verifies φ(i)2=−1\varphi(i)^{2}=-1, which is impossible since the square of any real number is non-negative.

So no such field homomorphism can exist.

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