Ivan Shishkin, Rye (1878)

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Hidden fractions

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Solution

Solution by Ancient Tree · EN

Let’s write 12\frac{1}{2} as a fraction with denominator 100100. This can be done by multiplying both the numerator and the denominator by 50:
12=1×502×50=50100\frac{1}{2}=\frac{1\times 50}{2\times 50}=\frac{50}{100}We want a fraction that is smaller than this, but not too small. So let’s choose 49100\frac{49}{100}. We now have to check that it is greater than 13\frac{1}{3}. The problem is that 13\frac{1}{3} cannot be written as a fraction with denominator 100.
But that’s fine: we can still rewrite both fractions to a common denominator, say, 300 :
49100=49×3100×3=14730013=1×1003×100=100300\frac{49}{100}=\frac{49 \times 3}{100 \times 3}=\frac{147}{300} \qquad\quad \frac{1}{3}=\frac{1 \times 100}{3 \times 100}=\frac{100}{300}So 49100\frac{49}{100} is between 13\frac{1}{3} and 12\frac{1}{2}.

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