Ivan Shishkin, Rye (1878)

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Ma première fonction à deux variables

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Solution

Solution by darktoaster · FR

f(1,2)=2⋅1+2=4f(1,2) = 2\cdot 1 +2 = 4
f(0,0)=2⋅0+0=0f(0,0) = 2\cdot 0 + 0 = 0
f(100,−1)=2⋅100+(−1)=199f(100,-1) = 2\cdot 100 + (-1) = 199

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