Ivan Shishkin, Rye (1878)

Discussions

Parties réelle et imaginaire de nombres complexes 1

0 messages

Back to problem

Solution

Solution by SalixBabylonica · FR

On a :

  1. ℜ(z1)=0\Re(z_{1})=0 et ℑ(z1)=1\Im(z_1)=1
  2. ℜ(z2)=34\Re(z_2)= 34 et ℑ(z2)=−5\Im(z_{2})=-5
  3. ℜ(z3)=5\Re(z_3) = 5 et ℑ(z3)=0\Im(z_3) = 0

No messages yet.