Ivan Shishkin, Rye (1878)

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Quotient of a group and subgroup

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Solution

Solution by Ancient Tree · EN

No, it is not necessarily the case. For example, with G=ZG=\mathbb{Z}, the subgroups of GG are of the form nZn\Z; but the quotients Z/nZ\Z /n\Z are not of this form since they are finite.

For a counter-example in the finite groups, it’s a bit less trivial.

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