Ivan Shishkin, Rye (1878)

Problems/Number theoryUnreviewed

P admet une infinité de diviseurs premiers

by Uettechat·
70
Difficulty scaleÉchelle de difficulté

This score reflects both the level of the required concepts and the difficulty of the solution.Ce score tient compte à la fois du niveau des notions nécessaires et de la difficulté de la résolution.

  1. 110First steps / middle schoolPremiers pas / collège
  2. 1125Beginner / high schoolDébutant / lycée
  3. 2650Intermediate / undergraduateIntermédiaire / licence
  4. 5170Advanced / graduateAvancé / master
  5. 7190Expert / specializedExpert / spécialisé
  6. 91100Research levelNiveau recherche
These levels are approximate guides.Ces niveaux sont des repères approximatifs.
·
Français

Showing the Français version because no English translation exists yet. Add that translation.

Unreviewed. This problem has not been reviewed by trusted users yet.

Soit PZ[X]P\in\mathbb{Z}[X] non constant.
On dit qu’un nombre premier pp divise PP si il existe un entier nZn \in \mathbb{Z} tel que pP(n)p | P (n).
Montrer que PP admet une infinité de diviseurs premiers.

I solved itMark it doneAdd to my listKeep it in your list

Solutions

0
Report

For an unclear, ambiguous, or possibly incorrect statement, please use the Discussion tab on the right. Report content that needs moderator intervention, such as dangerous, clearly non-mathematical, or plagiarized content.