SolutionSolution by SalixBabylonica · FROn a : z1=−4+7iz_1 = -4+7iz1=−4+7i donc ℜ(z1)=−4\Re(z_1)=-4ℜ(z1)=−4 et ℑ(z1)=7\Im(z_1) = 7ℑ(z1)=7 z2=32+2×3i+i2=9+6i−1=8+6iz_2=3^2+2\times3i+i^2 = 9+6i-1 = 8+6iz2=32+2×3i+i2=9+6i−1=8+6i donc ℜ(z2)=8\Re(z_2)=8ℜ(z2)=8 et ℑ(z2)=6\Im(z_2) = 6ℑ(z2)=6 z3=8i2×i+5+(−1)=−8i+4z_3=8i^2\times i+5+(-1) = -8i + 4z3=8i2×i+5+(−1)=−8i+4 donc ℜ(z3)=4\Re(z_3)=4ℜ(z3)=4 et ℑ(z3)=−8\Im(z_3) = -8ℑ(z3)=−8
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