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Déterminer la partie imaginaire des nombres complexes suivants :
- z1=5+i−9+6i
- z2=(3+i)2
- z3=(2i)3+5+i2
Solutions
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On a :
- z1=−4+7i donc ℜ(z1)=−4 et ℑ(z1)=7
- z2=32+2×3i+i2=9+6i−1=8+6i donc ℜ(z2)=8 et ℑ(z2)=6
- z3=8i2×i+5+(−1)=−8i+4 donc ℜ(z3)=4 et ℑ(z3)=−8