Ivan Shishkin, Rye (1878)

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Limit of a periodic function

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Solution

Solution by Ancient Tree · EN

Let x∈Rx\in \R be an arbitrary real number, and consider the sequence f(x),f(x+T),f(x+2T),…f(x),f(x+T),f(x+2T),\ldots . By assumption, since x+nT⟶n→+∞+∞x+n T \underset{n \rightarrow+\infty}{\longrightarrow}+\infty, it converges to a limit l∈Rl\in \R. But this sequence is constant by periodicity of ff. This means that f(x)=lf(x)=l. Applying the same reasoning for every x∈Rx\in \R, we get that ff is constant, equal to ll.

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