Let be a non-constant polynomial with complex coefficients.
It is necessarily the case that any of its roots verify ?
Solutions
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Assume the inequality holds for any root of any complex polynomial of degree at least .
Then any root of is also a root of where is a non-nul complex number. Hence if is a solution of the inequality for then it has to be a solution for . Hence, for all :
But then one can let goes to so has to be zero. But there exists polynomials which roots are not zero thus this is our contradiction.
