Soit unitaireEN et . Montrer que si est scindé sur , alors toutes ses racines ont le même dénominateur sous forme irréductible.
Solutions
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Let (lowest terms) be one root and put , a monic polynomial with integer coefficients. Then is an integer, so is monic in , and its rational roots, which are times the roots of , are integers. So every root has denominator dividing ; running the argument from each root, the denominators all coincide.
