Ivan Shishkin, Birch Grove

Residue theorem

Theorem / Complex analysis / Stub

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Intuition

The Residue theorem claims that the integral over a closed curve of a meromorphic functionFR only depends on the function poles
included in the curve.

Enoncé du théorème

Let ff be a meromorphic function over a simply connected open UCU\subset \mathbb{C} with n isolated pole(s): the (pi)i[ ⁣[1,n] ⁣](p_{i})_{i\in [\![1,n]\!]}
Then we define γ:[0,1]C\gamma :[0,1] \mapsto \mathbb{C} a cloed continuous closed curve[ (γ(0)=γ(1))\left(\gamma(0)=\gamma(1) \right)]. Then, we have : γf=k=1n2iπ.Ind(γ,pk).Res(f,pk)\int_{\gamma}f=\sum_{k=1}^n2i\pi.Ind(\gamma,p_{k}).Res(f,p_k)
With Ind(γ,p)Ind(\gamma,p) the number of ... γ\gamma does around de p et Res(f,p)Res(f,p) the coefficient a1a_{-1} of 1zp\frac{1}{z-p} in the Laurent serie expansion of the function f around c.

Examples :

 For:γ:[0,1]Cteiπt- We have: γsin(z)dz=0- We have to: γdzz=2iπ\text{ For:} \\ \gamma: [0,1] \mapsto \mathbb{C}\\ t \mapsto e^{i\pi t}\\\text{- We have: }\int_{\gamma}sin(z)\mathrm{d}z=0 \\ \text{- We have to: }\int_{\gamma}\frac{dz}{z} = 2i\pi

Practice this concept with exercises

  • Déterminer la valeur des intégrales suivantes:

    1. Pour γ ⁣:t[0,1]e2iπt\gamma\colon t\in [0,1]\longmapsto e^{2i\pi t}, γezzdz\displaystyle\int_{\gamma}\frac{e^z}{z}\,\mathrm{d}z.
    2. Pour γ ⁣:t[0,1]1+2e4iπt\gamma\colon t\in [0,1]\longmapsto 1+2e^{4i\pi t}, γcos(z)zdz\displaystyle\int_{\gamma}\frac{\cos(z)}{z}\,\mathrm{d}z.
    3. Pour γ ⁣:t[0,1]e2iπt\gamma\colon t\in [0,1]\longmapsto e^{-2i\pi t}, γ1sin(z)dz\displaystyle\int_{\gamma}\frac{1}{\sin(z)}\,\mathrm{d}z.
    4. Pour γ\gamma le rectangle, considéré dans le sens anti-horaire, de sommets 0,2,2+2i0, 2, 2+2i et 2i2i, γz(z1)2dz\displaystyle\int_{\gamma}\frac{z}{(z-1)^2}\,\mathrm{d}z.
    Open exerciseDifficulty 48/100 · 0 solutions · 0 hints
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